If it's not what You are looking for type in the equation solver your own equation and let us solve it.
0=3x^2+5x-36
We move all terms to the left:
0-(3x^2+5x-36)=0
We add all the numbers together, and all the variables
-(3x^2+5x-36)=0
We get rid of parentheses
-3x^2-5x+36=0
a = -3; b = -5; c = +36;
Δ = b2-4ac
Δ = -52-4·(-3)·36
Δ = 457
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{457}}{2*-3}=\frac{5-\sqrt{457}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{457}}{2*-3}=\frac{5+\sqrt{457}}{-6} $
| 43x+1+16x+2=180 | | X-119=x-6(2+7) | | (x-5)=19 | | -10k=7-9k | | X-8/3=x+2/8 | | 011x=100 | | -10f=7-9f | | 9x-3+12x-4+40=180 | | 2x+17=-2+-3 | | 11h+19=1+13h | | 3x-3(5x+3)=14-2x | | (0.5m+6)+m=75 | | 2m+7+m=1-5m-10 | | -4(4+x)=8 | | 4(4+x)=8 | | -18-2d=14-10d | | 6-4x=7x-9x6 | | 11x^2+6x=-2 | | x+29=4x+12 | | 3(x–4)=12 | | 6(4x-4)=-240 | | 118+(8x-10)=180 | | 5(y-1)/4=1-2y | | x+13-3x=2+x-1 | | 4(3-3(x+1))+1=2(-43-x)+2x+43 | | 6x^2+6x=-2 | | (2x-6)/3=(x+8)/2 | | y=100+0.75y | | (13(12)-38)+(8x-10)=180 | | x+17-5x=3+x-1 | | (x-5)(x+5)=(x-7)(x+4) | | 2x^2-x+2=-11 |